Question
Find an equation of variation for the given situation.The volume $V$ of a given mass of a gas varies directly as the temperature $T$ and inversely as the pressure $P$. If $V=231 \mathrm{cm}^{3}$ when $T=42^{\circ}$ and $P=20 \mathrm{kg} / \mathrm{cm}^{2},$ what is the volume when $T=30^{\circ}$ and $P=15 \mathrm{kg} / \mathrm{cm}^{2} ?$
Step 1
This can be written as $V = k \frac{T}{P}$, where $k$ is the constant of variation. Show more…
Show all steps
Your feedback will help us improve your experience
Erika Bustos and 80 other Calculus 3 educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
Find an equation of variation for the given situation. Boyle's Law. The volume $V$ of a given mass of a gas varies directly as the temperature $T$ and inversely as the pressure $P$. If $V=231 \mathrm{cm}^{3}$ when $T=42^{\circ}$ and $P=20 \mathrm{kg} / \mathrm{cm}^{2},$ what is the volume when $T=30^{\circ}$ and $P=15 \mathrm{kg} / \mathrm{cm}^{2} ?$
More on Functions
Variation and Applications
The volume $V$ of a given mass of a gas varies directly as the temperature $T$ and inversely as the pressure $P .$ If $V=231 \mathrm{cm}^{3}$ when $T=300^{\circ} \mathrm{K}$ (Kelvin) and $P=20 \mathrm{lb} / \mathrm{cm}^{2},$ what is the volume when $T=320^{\circ} \mathrm{K}$ and $P=16 \mathrm{Ib} / \mathrm{cm}^{2} ?$
Rational Expressions, Equations, and Functions
Formulas, Applications, and Variation
The volume $V$ of a given mass of a gas varies directly as the temperature $T$ and inversely as the pressure $P .$ If $V=231 \mathrm{cm}^{3}$ when $T=300^{\circ} \mathrm{K}$ (Kelvin) and $P=20 \mathrm{lb} / \mathrm{cm}^{2}$ what is the volume when $T=320^{\circ} \mathrm{K}$ and $P=16 \mathrm{lb} / \mathrm{cm}^{2} ?$
Transcript
18,000,000+
Students on Numerade
Trusted by students at 8,000+ universities
Watch the video solution with this free unlock.
EMAIL
PASSWORD