00:01
Here we want to show that the variance of two events is not necessarily equal to the sum of their independent variances.
00:27
Okay, so take, for example, a coin flip.
00:31
So the probability of getting heads is going to be equal to the probability of getting a tails, which is one half, right? and so we get that the probability of getting a heads plus the probability of getting a tails is going to be equal to one.
00:51
It's one half plus one half.
00:54
So we consider the expected values.
00:58
Okay, so the expected value of getting a heads would be equal to the sum of the product of each possibility with its probability, right? so it's going to be equal to the sum of each possibility multiplied with its probability.
01:41
Okay, so that's going to end up being either you didn't get it with a probability of one -half, or you got your heads with a probability of one -half is equal to one -half.
01:56
And by the exact same argument, you will see that this is the expected value of getting a, tails as well.
02:08
Okay, and the expected value of both events would then be equal to the, you know, we use the exact same definition, but with it, by adding them together.
02:34
So this is going to end up being 1 times 1 is equal to 1.
02:43
And if you want to look at the expected value of a squared or for x squared, so this is going to help us set up calculating our variances, right? because by definition, the variance, of x is equal to the expected value of x squared minus the expected value of x squared.
03:21
Okay, so we're going to calculate this, and this is basically the same.
03:29
It's up here, except we're going to square our x, right? so this is going to end up being equal to 0 squared times 1 half plus 1 squared times 1 1 half is equal to 1 half and again by the same argument and see if this is equal to the expected value of getting a tails squared now i want to consider the expected value of getting the heads and tails squared okay and by the same argument it's going to be the same as up here except with a where we are squaring that value as well and so then we get 1 squared times 1 1 is equal to 1...