Question
Find an explicit solution of the given initial-value problem.$$x^{2} \frac{d y}{d x}=y-x y, \quad y(-1)=-1$$
Step 1
We divide both sides by $x^{2}y$ and rearrange the equation to get: $$\frac{1}{y} \frac{dy}{dx} = \frac{1}{x^{2}} - \frac{1}{x}$$ Show more…
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