00:01
Okay, so we can consider our given matrix here.
00:05
So a is the matrix 111, and then 1, 2, 3, 4.
00:08
So we know that the kernel of a of a linear transformation is the solution set of the linear system, ax equals 0.
00:15
So we're looking at the matrix here, 1111, 4, x, ax equal 0.
00:30
So we can solve this by using gaussian elimination.
00:33
So we can reduce our row, and we get that the row, reduced, um, echelon form of a is going to be 1, 0, negative 1, 2, and then 0, 1, 1, 3...