Question
Find and graph the polynomial of minimal degree that passes through the following points:(a) $(3,-1),(6,5)$;(b) $(-2,4),(0,6),(1,10)$;(c) $(-2,3),(0,-1),(1,-3)$;(d) $(-1,2),(0,-1),(1,0),(2,-1)$;(e) $(-2,17),(-1,-3),(0,-3),(1,-1),(2,9)$.
Step 1
Since there are two points, the polynomial of minimal degree that can pass through these points is a line (degree 1). **Step 2:** Use the point-slope form of a line equation, \( y - y_1 = m(x - x_1) \), where \( m \) is the slope and \( (x_1, y_1) \) is a point Show more…
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