00:01
Okay, so in this problem, we will be pointing the radiated resistance and also its associated power, right? so it is nothing that c is equal to 1 over square root, mu not, times epsilon not, and this is equal to lambda, omega, or 2 pi, right? so the radiating power can be written as p is equal to d, e with respect to t.
00:37
And this is equal to q square, omega, pore, x, not square, and whole divided by 12, pi epsilon, not, c, cube, right? okay, so let this is equal to, this is equal to omega square, x not square, and, divided by a 12 pi epsa la.
01:04
Lambda square right omega square lambda square omega square and this is this is omega square times q right and it is p is equal to let put the value up see here and simplification and simplifying here right so this is equal to 4 pi square x omega square let write this clear so this is 4 pi square right times omega square and x not square right and divided by 12 pi epsilon nought lambda square omega square right time square root new not epsilon not and i not square okay so p is equal to 1 over 2 cross 2 pi over 3 and this is square root m nought over epsilon not and this is times x not over lambda and this is whole square i not square right so the power is which is equal to and let let find the radius the resistance bus right so let the resistance is equal to 2 pi over 3 times mu not over epsilon not and x not who are lambda whole square and this is equal to set 787 and times x not over lambda whole square om right so this is oom okay so by substitution of the given parameters, the wavelength is given by limda is equal to e over c, right? and this is equal to 3 times 10 to the power 8 over pipe, times 10 to the power pipe...