00:01
Is a problem about simplifying a circuit and the circuit looks kind of ugly because the circuit has several diagonal resistors and parallel branches but as we'll see we can redraw that and make things simpler.
00:16
We're going to use the fact that the total resistance is for our parallel circuit the reciprocal of the sum of the reciprocals.
00:27
We're going to use that in a couple of places but we need to redraw that circuit or i wanted to redraw that circuit to make it a little more clear and when you do then you end up with the first branch is 12 oms and then there's another branch with six oms and then there's another branch with three oms and then that splits off into two and three and three and 4 and 2 is really how that circuit work that being the case of course these are in series so they just become 6 oms and so then i have this first set of parallel branches is right here and so their total resistance is going to be 1 over 1 over 2 plus 1 over 3 plus 1 over 6 that's going to be one ome.
01:46
And so then this second branch here, or i'm sorry, this third branch here, is going to have just one resistor addition to it.
01:59
That's one ome.
02:00
And so it is as though i have 12, 6, and 4 in parallel.
02:11
That being the case, then the resistance, a to b is equal to 1 over 1 over 12 plus 1 over 6 plus 1 over 4...