We can rewrite these equations in slope-intercept form \(y = mx + b\).
For the first line \(3x - 4y + 1 = 0\):
\[
4y = 3x + 1 \implies y = \frac{3}{4}x + \frac{1}{4}
\]
The slope \(m_1\) of the first line is \(\frac{3}{4}\).
For the second line \(5x + 12y - 2 =
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