Question
Find equations of the tangent plane and normal line to the surface at the given point.$$z=e^{-x^{2}-y^{2}} \text { (a) (0,0,1) and (b) } \left(1,1, e^{-2}\right)$$
Step 1
The partial derivative with respect to $x$ is given by: $$\frac{\partial z}{\partial x} = -2xe^{-x^{2}-y^{2}}$$ Similarly, the partial derivative with respect to $y$ is given by: $$\frac{\partial z}{\partial y} = -2ye^{-x^{2}-y^{2}}$$ Show more…
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