find-f-1-if-fx2-x2-x-2

Name: find f 1 if fx2 x2 x 2
Uploaded: 2020-06-14
Duration: 32 s
Channel: Numerade
Description: Find $f(-1)$ if $f(x)=2 x^{2}-x$.

Question

Find $f(-1)$ if $f(x)=2 x^{2}-x$.

Karly Williams · Accepted Answer

Okay, So we need if on f of negative one if f of x equals two x squared minus sexed. So we&#x27;re gonna dio is there to Tom&#x27;s negative one squared minus a negative one. So negative one squared turns in tow one. So two times one and then we have minus negative one, which is just gonna turn into pull us one, because the negative cancel Well, so two times one is two plus one is three. So f negative one equals.

Carson Merrill · Answer

So here for this problem were given F double prime of X to be equal to one over X squared. And I&#x27;m gonna write that as X to the negative too. Then I&#x27;ll make it simpler for us in the long run, that tells us that F prime of X is going to be X to the negative one over a negative one, which is just negative one over Acts plus C. That tells us that F of X is going to be equal to negative the anti derivative of one over X is actually going to be the natural log of the absolute value of X. So then based on that, what we end up having is um plus C. X. Class D. Um And the reason why we have plus six is because this is some constant. So it&#x27;s anti derivative of B plus C X. And then we have plus D. For the final general constant.

Taylor Shimono · Answer

So for this problem, we know that in order to find our derivative, we couldn&#x27;t do this using the product rule. I&#x27;m so taking the derivative of each of these parentheses individually. But instead I find it easier to just simplify as much as we can right away and then differentiate. I&#x27;m so I&#x27;m going to rewrite this as X plus x of the negative one power times X squared minus X of the negative to power. And from here, I&#x27;m just going to factor out each of my terms. And when I do that, I get excited. Third power minus excellent negative one power plus X of the first power minus X the negative three power. And from here we can go ahead and differentiate. I&#x27;m so f prime of X is going to be equal to of the derivative of X cube. You know, we move this three to the front as a coefficient, and then we raise X to the power of three minus one. So three X squared minus the derivative of X, A negative one power. This negative one is going to be a coefficient, says actually end up in plus X the power of negative one minus one. So to the negative to power plus the derivative derivative of X, the first power is just one and finally minus the derivative of X, A negative three power well again and upping plus three x to the negative fourth power.

Clarissa Noh · Answer

it&#x27;s clear. So when you read here, so we have f of X is equal to X over X square minus one. We&#x27;re gonna use the quotient role. We&#x27;ll get X square minus one D acts d over DX minus x times D over D X X square minus one well over X square minus one square just becomes equal to X square minus one minus two X square over X square minus one square, which is equal to negative X square minus one over X square minus one square. We&#x27;re gonna find the second derivative by using the Kocian rule, which is X square minus one square D over DX your negative X square minus one minus negative X square minus one de over de x X square minus one square All over X square minus one square. You square that again, this becomes equal to that&#x27;s square minus one times negative. Two acts less negative. Two X square minus two turns negative. Two acts well over X square minus one. Cute. You could simplify this to two x times X square plus three all over X square minus one. Cute

David Mccaslin · Answer

So in this problem we are asked to find f prime at a when half of x is X to the -2. Well, by definition, if private A Is the limit as H approaches zero of F. Of a plus H minus F of a over H. All right. So that means that this is now the limit as h approaches zero F of a plus age and in this function F of X. So that is one over a plus H squared minus one over a squared all that is over eight. All right. So that means I have a limit as H goes to zero then of what? When I get a common denominator in the top. All right. And so I&#x27;ll have a squared coming on top and then combine the fractions. That means I&#x27;ll have a squared minus a squared plus two. A H plus H squared all over a squared times A plus H squared times H from the from the denominator previously. All right. So like this a squared minus at a square is but those two are gonna be gone, aren&#x27;t they? So that means I have the limit as h goes to zero of minus to a H plus H squared over a squared times A plus h squared H. But I have an H in each term in the numerator so I can cancel one of those out. Can&#x27;t I like that? So, that means I now have the limit As a joke goes to zero of minus to a plus H over a squared times A plus H squared. Okay, so taking now the limit as H goes to zero in the numerator, I&#x27;m just left with minus two way, aren&#x27;t I? And the denominator. I have a squared times A squared, right? Because H goes to zero. So A plus H just goes to a square that let&#x27;s just a square. So that means I&#x27;m left with -2 A over eight of the 4th. Well I can cancel 1, 1 of those AIDS out. and so that means I&#x27;m left with -2 over a cute is our derivative If prime it ain&#x27;t.

Clarissa Noh · Answer

hands clear. So when you right here, so we have a pup. Acts is equal to x square over one plus X. We&#x27;re gonna difference she using the quotient rule to find the first year of it to get one plus x d over d X for X square minus x square d over DX for one plus x. This becomes equal to all over one plus square. This becomes equal to one plus x times two x minus X square times one over one plus x square just equal to two x plus x square over one plus x square. We&#x27;re gonna find the second derivative Using the closure role, we get one plus x square D over DX go to X plus X square minus two X plus x square Do you over d x one plus x square all over one plus X square needs. Square that again and this becomes equal to one plus x times two plus two x minus two times two X plus x square all over one plus x cute. We just have to plug in X is equal to one. Then we get, uh, off. The second derivative of one is equal to 14 Yeah,

Problem

Factor the expression $6 x^{2}+x-2$.

Problem 1 Easy Difficulty

Find $f(-1)$ if $f(x)=2 x^{2}-x$.

Answer

3

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