00:01
Okay, so in this question we're asked to find the inverse of this function and then to plot both the function and the inverse.
00:08
So let's start with the inverse, right? you remember the typical technique is to write y equals to the function and then solve with respect to x.
00:16
So in this case, we obtain y minus 1 is equal to x squared.
00:21
And from here we concluded x must be, so if x squared is equal to this, we take the square root.
00:27
So x must be positive or negative y minus 1 but because we are working in the condition x greater than or equal to 0 we take the positive sign right so in reality x is exactly equal to the square root of y minus 1 and the domain in here of course will be for y greater than or equal to 1 right so conclusion our even inverse function let's write f minus 1 of y to be clear will be the square root of y minus 1 and its domain will be y greater than or equal to 1.
01:01
Okay, so let's make a plot here for f.
01:06
So this will be positive values of x, right? so this will be f of x and it will be x and x squared plus 1 is a parabola.
01:15
We're only interested in positive values of x...