💬 👋 We’re always here. Join our Discord to connect with other students 24/7, any time, night or day.Join Here! # Find $f$.$f"(x) = 8x^3 + 5$, $\quad f(1) = 0$, $\quad f'(1) = 8$

## $f(x)=\frac{2}{5} x^{5}+\frac{5}{2} x^{2}+x-3.9$

Derivatives

Differentiation

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##### Top Calculus 2 / BC Educators  ##### Kristen K.

University of Michigan - Ann Arbor ##### Michael J.

Idaho State University Lectures

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### Video Transcript

given the second derivative, let's first find the first derivative. In other words, take the integral. So make the experiment one more derived by the new exponents. This is when C equals one. Now we're finding the integral again. So in other words, the original function D equals negative 3.9 There for the original function after box is to fifth xfff post five over too X squared plus X minus 3.9 or plus RC. #### Topics

Derivatives

Differentiation

Volume

##### Top Calculus 2 / BC Educators  ##### Kristen K.

University of Michigan - Ann Arbor ##### Michael J.

Idaho State University Lectures

Join Bootcamp