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Find $ f $.

$ f"(x) = 8x^3 + 5 $, $ \quad f(1) = 0 $, $ \quad f'(1) = 8 $

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$f(x)=\frac{2}{5} x^{5}+\frac{5}{2} x^{2}+x-3.9$

02:27

Wen Zheng

Calculus 1 / AB

Calculus 2 / BC

Chapter 4

Applications of Differentiation

Section 9

Antiderivatives

Derivatives

Differentiation

Volume

Missouri State University

Baylor University

Boston College

Lectures

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given the second derivative, let's first find the first derivative. In other words, take the integral. So make the experiment one more derived by the new exponents. This is when C equals one. Now we're finding the integral again. So in other words, the original function D equals negative 3.9 There for the original function after box is to fifth xfff post five over too X squared plus X minus 3.9 or plus RC.

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