Question
Find $ f $.$ f"(x) = 8x^3 + 5 $, $ \quad f(1) = 0 $, $ \quad f'(1) = 8 $
Step 1
To find the first derivative, we need to integrate the second derivative with respect to $x$. So, $f'(x) = \int f''(x) dx = \int (8x^3 + 5) dx = 2x^4 + 5x + C_1$, where $C_1$ is the constant of integration. Show more…
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Find $f$ . $f^{\prime \prime}(x)=8 x^{3}+5, \quad f(1)=0, \quad f^{\prime}(1)=8$
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