Question
Find $f^{(9)}(0)$$$f(x)=x \cos x^{2}$$
Step 1
We know that $\cos x = 1 - \frac{x^2}{2!} + \frac{x^4}{4!} - \frac{x^6}{6!} + \cdots$. Substituting $x^2$ for $x$ in the expansion, we get $\cos x^2 = 1 - \frac{x^4}{2!} + \frac{x^8}{4!} - \frac{x^{12}}{6!} + \cdots$. Show more…
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