00:04
Okay, f of x is equal to 2x q plus 1 and we want to find f prime of 1 by taking the limited as h approach is 0 of the difference quotient f of 1 plus h minus f of 1 over h.
00:20
So this is going to equal to the limit as h approaches 0 of f of 1 plus h, meaning we're going to substitute 1 plus h into the f of x function everywhere you see x.
00:36
So 2 times 1 plus h cubed and then plus 1.
00:55
So f of x is 2x cubed plus 1, so f of 1 plus h is 2 times 1 plus h cubed plus 1.
01:03
So 2 times 1 plus h cubed plus 1.
01:06
Then we need to subtract f of 1.
01:10
So f evaluated when x is 1, plug 1 in for x, 2 times 1 cubed.
01:22
Plus 1.
01:24
So that is f of 1.
01:30
Then all of that needs to be put over h and we will take the limit of this expression as h approaches 0.
01:38
But first we need to expand this a little bit.
01:41
So 1 plus h cubed expands out to be 1 cubed plus 3 times 1 squared times h.
02:05
So 3 times h.
02:06
So 3 times 3 times 1 squared times h plus 3 times 1 times h squared plus h cute.
02:31
So this portion in the parentheses raised to the third power has the expansion you see up here written in blue.
02:44
And then simplifying what's in this parentheses, 1 cubed is 1, so 2 times 1 is 2 plus 1 is 3.
03:06
So we are taking the limit as h approaches 0.
03:16
Okay, now all of this needs to be times by 2.
03:21
And then we need to add 1, and then we need to subtract this, which is 3.
03:27
So let's put brackets around this 1 plus h cubed equals distance, entire expression written in blue...