0:00
Hi there.
00:01
In this problem, we're asked to find the partial derivatives with respect to x and y of this function.
00:06
So let's begin with the partial respect to x.
00:10
Now before we even do this, why don't we rewrite the original function just a little bit so that it looks like what it means.
00:17
The way we write the 2 is always a little confusing in my opinion.
00:22
So remember what this means is sine of x minus 3y and that whole result is squared.
00:29
So that's what the original function actually says.
00:32
When we write it like this, it looks a little bit more like the chain rule that we're going to need.
00:38
When we take the derivative, we start as we always would from the outside in.
00:43
In other words, this two comes out in front where let's treat this whole thing like a power rule.
00:47
Two to a bunch of stuff is two times that stuff.
00:52
X minus three line there.
00:54
Okay.
00:55
All to the first power, we drop the power by one.
00:57
And now we need to multiply by the derivative of all this inner stuff.
01:05
Now when we say derivative, in this case we mean the partial derivative with respect to x of all this stuff in the middle.
01:17
So we'll just copy everything here.
01:20
The power is one here so we can just get rid of those brackets.
01:26
Okay, now what is the partial derivative of with respect to x of sine of x minus 3y? notice we have another chain rule.
01:33
We have this x minus 3y inside of a sign.
01:38
So the derivative of sine, first of all, is cosine.
01:44
We always leave the inner function intact.
01:48
And now the second rule, the chain rule is kicking in.
01:51
We need to multiply by the derivative of this stuff.
01:56
So let's keep writing partial derivative with respect to x.
01:59
We always mean partial with respect to x in this case when we say derivative of x minus 3y.
02:06
Okay, so we're almost done.
02:07
We just had to unravel this using the chain rule twice...