The antiderivative of $1$ is $x$.
The antiderivative of $e^x$ is $e^x$.
The antiderivative of $\frac{1}{x}$ is $\ln|x|$.
So the antiderivative of $1+e^x+\frac{1}{x}$ is $x+e^x+\ln|x|+C$, where $C$ is the constant of integration.
Now, we can find the
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