We have $f'(x) = 3x^2 - 6x$. To find $f(x)$, we need to integrate $f'(x)$ with respect to $x$:
$$f(x) = \int (3x^2 - 6x) dx = \int 3x^2 dx - \int 6x dx$$
Now, we integrate each term:
$$f(x) = 3\int x^2 dx - 6\int x dx = 3\cdot\frac{1}{3}x^3 -
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