Question
Find $f(x)$ by solving the initial value problem.$$f^{\prime}(x)=3 x^{2}+4 x-1 ; f(2)=9$$
Step 1
The antiderivative of $3x^2$ is $x^3$, the antiderivative of $4x$ is $2x^2$, and the antiderivative of $-1$ is $-x$. So the antiderivative of $3x^2 + 4x - 1$ is $x^3 + 2x^2 - x + C$, where $C$ is the constant of integration. Show more…
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