00:01
This problem is a parallel circuit, and it has an independent, a dependent current source in it, and it has a couple of branches with resistors in it.
00:13
And so we're just going to use kirchhoff's current law, which says that in any particular node, some of the currents is equal to zero, or the currents coming in are equal to the currents going out.
00:26
The other thing that we're going to rely on is that the voltage drive, across each of those branches is the same.
00:34
And i'm just going to call that v .s.
00:37
It's done that way in other problems as well.
00:40
So i'm just going to say that across each of those branches, i have a voltage drop of v .sub.
00:45
So now i can pick a node and i can get to work.
00:48
So i'm going to pick the top node on the left hand side.
00:52
And out of that node, i have the voltage source.
00:56
I'm going to call that positive, or the current source, rather.
01:00
And that is 2v.
01:01
X over k.
01:03
That's coming out of that node.
01:06
Also coming out of that node i have a branch with two resistors, one and two kilo -ooms.
01:13
And i know that the voltage across it is v -sab -s.
01:16
So the current there is v -sub -s over 3k, over 3 kilooms.
01:21
I also have 12 over k amps coming into it from that next branch to the right.
01:28
So minus 12 over k.
01:30
And then the last branch on the left.
01:34
I have current coming out of the node, that is vs over 6 kilooms.
01:41
The other thing i know is in that second branch...