00:01
To integrate this, note that we can rewrite this into the integral of 1 over the square root of negative of x squared minus 3x and then dx.
00:12
And then in here we want to complete the square.
00:15
We have the integral of 1 over.
00:18
We have the square root of negative of x squared minus 3x.
00:24
And then we add a term b over 2 squared where b is the coefficient of x.
00:29
So that'll be 3 over 2 squared.
00:32
And since we're adding the term negative of 3 over 2 squared, since this is affected by this negative, then we'd have to add a positive of that, since it's not part of the original form.
00:49
So it would seem like adding nothing.
00:53
And then we have dx.
00:55
And simplifying that, we have the integral of 1 over the square of 9 over 9 over 4 minus.
01:03
We have the square of x minus 3 over 2 and then d x...