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Find $\lim _{x \rightarrow 0^{+}} \frac{x \sin (1 / x)}{\sin x}$ if it exists.
$=1 \cdot$ A finite (but not fixed) quantity between -1 and 1 the limit does not exist.
Calculus 1 / AB
Chapter 3
TOPICS IN DIFFERENTIATION
Section 6
L Hopital's Rule; Indeterminate Forms
Functions
Limits
Derivatives
Differentiation
Continuous Functions
Applications of the Derivative
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we have the limits as X goes to zero from the positive side of X Sign of one over X divided by sine X. Now, one of things we can do is split this up. Um, here, we're going to assume that the limit does exist so that we can split up, split it up into two limits. Notice that this first limit Now we can apply low petals rule because we get 0/0. The second limit stays the same. Okay, the first limit is equal toe one. And because it is a finite non zero number, it follows that this limit does not exist because sign is oscillating me to negative one and one.
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