00:01
Okay, we are going to be finding our center of mass that would be the area between these two equations, and we have a thickness of that density row.
00:16
So first of all, if we just find the full mass of our system, that's going to be our cross -sectional area multiplied by row.
00:23
So that will be our function minus our other functions, so we're going to be actually subtracting a zero.
00:31
Now, if we put the two equal to each other and we factor out a y, we can see that they actually connect at y equals zero and y equals two.
00:40
So we'll be integrating from zero to two of my function 2y minus y squared minus zero.
00:47
So we don't really need to write the minus zero.
00:49
So we're ready to integrate.
00:51
So we go up a power reciprocal, which will get us to a y squared and then minus eight one third, y to the third.
00:58
We'll place in our two.
01:00
Of course placing in the zero zero is everything out so really just need to place in our value of two and we get four -thirds of row now our moment around why because that's used for the x -p so we'll find that first um that's going to be we're factoring out the half but we take the um difference multiplied by the sum of those so really it's going to be the same because of the zero and so we're just squaring it but we do need to square that out before we go to integrate.
01:34
So once it is squared, we're ready to go ahead and integrate...