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Find $$\mathbf{a}+\mathbf{b}, 2 \mathbf{a}+3 \mathbf{b},|\mathbf{a}|, and |\mathbf{a}-\mathbf{b}|$$$$\mathbf{a}=[4,1], \quad \mathbf{b}=[1,-2]$$

$|a-b|=\sqrt{9+9}=\sqrt{18}$

Calculus 3

Chapter 8

Vectors and Matrix Models

Section 2

Vectors

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Okay, So is for one. Be is one negative two to a plus B is four plus one and then one plus negative, too. Right. Then you have to A plus three B to a plus. Three feet is too. So to a is eight. Cover one. Right. So eight, come off. +13 V is one. I'm a negative six. Our final answer is 11 from a negative fires. That's our natives. Uh, big stuff tonight. Yeah, this negative four. Okay, then the magnitude of a is the square root off four squared, plus one square square, rich of 16 plus once of the square roots of 17. And then finally we have a minus V, which is equal to four minus one comma, one minus negative tubes. That's one plus two. So it's three from a, uh three.

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