In this case, the only constraint involving $x$ and $y$ is $ax + by \leq 1$. For the linear program to be infeasible, we must have $ax + by > 1$ for all $x, y \geq 0$. This is only possible if both $a$ and $b$ are non-positive, i.e., $a \leq 0$ and $b \leq 0$. So,
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