$$
Now, let's prove this equality using the Pascal's identity:
$$
\left(\begin{array}{l}
n \\
k
\end{array}\right) = \left(\begin{array}{l}
n-1 \\
k-1
\end{array}\right) + \left(\begin{array}{l}
n-1 \\
k
\end{array}\right).
$$
Applying Pascal's identity to each
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