00:01
In this question, a function is given as x -resied to the power 5, minus 3x raised to the power 4, minus 3x cube plus 9x square, minus 4x plus 12.
00:14
We need to find out the rational zeros of this function.
00:19
We can see the degree of this function is 5, so this function can have at most 5 zeros.
00:26
Now according to rational zeros theorem, any rational 0 of a function can, be of form p upon q and the possibilities for this p and q are the possibility for p is are the factors of the last term which is 12 so the possibilities for p are plus minus 1 plus minus 2 plus minus 3 plus minus 4 plus minus 6 and plus minus the possibility for q are the factors of the coefficient of the leading term.
01:19
The coefficient of the leading term is 1.
01:21
So the factors of 1 are plus and minus 1.
01:25
So possibilities for q are plus minus 1.
01:31
Now from here we can figure out the possibilities of p upon q.
01:38
So the possibilities for p upon q are plus minus 1 plus minus 2.
01:45
Plus minus 3 plus minus 4 plus minus 6 and plus minus 12 we can see there are so many possibilities for the ratio zeros of this function but there can be a very few now we will check one by one for all these zeros possible zeros of this function but we will terminate when we get enough now we can use substitution method to check these numbers whether these are zeros of this function or not, but we will use synthetic division as synthetic division is more beneficial because the question during that synthetic division can be used for factization of that function.
02:51
So for one, we will check using synthetic division.
02:58
The coefficients of this function are 1, minus 3, minus 3, 9, minus 4, and 12.
03:18
Now we will use this.
03:24
First 1 is 0, so 1 plus 0 is 1.
03:29
Now 1 multiplied 1 is 1.
03:32
So here it is 1, minus 3 plus 1 is minus 2.
03:36
Minus 2 multiplied by 1 is minus 2 here we get minus 5 and minus 5 multiplied by 1 is minus 5 from here we get 4 4 multiplied by 1 is 4 here it is 0 1 multiplied by 0 is 0 now 12 minus 12 plus 0 is 12 so the remainder is not 0 from here we get f of 1 is not 1 from here we get f of 1 is not equal to 0.
04:14
Hence, 1 is not a 0 of this function.
04:19
Now we will move forward to check 2 as a 0 of this function.
04:31
We will use 2 for combining whether it is 0 is not...