00:01
Here i want to find the line equation parallel to the one on the left, but going through 1 negative 1 .1.
00:13
Now, the first step, if i rewrite the line equation on the left as this, x plus 2 over 1 equals y over 2, equals z minus 3 over 1.
00:28
If you have x, y, z on top, whereas 1x, 1y, 1, 1 z, or plus, then on the bottom 121 is the line direction.
00:41
So i know at once that this line has vector 121, so 1, 2 ,1 as its direction.
00:53
Now, i can write the general line equation as r equals a plus, t times b where a is a point on the line which here is 1 negative 1 1.
01:14
So i write here 1 negative 1 plus t and the line direction is 1 2 1.
01:31
Now what they want first of all is the answer in parametric form so remember r is simply x y z so x, y, z.
01:48
And just read off the answers...