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Find parametric equations for the line segment from $ (-2, 18, 31) $ to $ (11, -4, 48) $.
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$x=-2+13 t, \quad y=18-22 t, \quad z=31+17 t, \quad 0 \leq t \leq 1$
Vectors and the Geometry of Space
Equations of Lines and Planes
Johns Hopkins University
Missouri State University
Oregon State University
In mathematics, a vector (from the Latin word "vehere" meaning "to carry") is a geometric entity that has magnitude (or length) and direction. Vectors can be added to other vectors according to vector algebra. Vectors play an important role in physics, engineering, and mathematics.
In mathematics, a vector (from the Latin word "vehere" which means "to carry") is a geometric object that has a magnitude (or length) and direction. A vector can be thought of as an arrow in Euclidean space, drawn from the origin of the space to a point, and denoted by a letter. The magnitude of the vector is the distance from the origin to the point, and the direction is the angle between the direction of the vector and the axis, measured counterclockwise.
Find parametric equations …
Find the parametric equati…
So again, we want to find the parametric equation for the line segment minus two, 18, 31 two, 11 -4 and 48. Again, this is my there's no doubting that I'll start here And then my normal vector and is just 11 last two -4 -18. And then 48 when is 31? It was just 13 minus 22 Than seven in 17. So they question is a Last three times and was his -2 18, 31. Last three times 13 -20- 17. This is my anguish. Yeah. And then we wanted to start at minus 2 18 and 31. So he must start from zero And then must change at 11 -4 and 48 13 must end at one. That's it. That stands
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