Question
Find parametric equations of the line tangent to the graph of $\mathbf{r}(t)$ at the point where $t=t_{0}$.$$\mathbf{r}(t)=e^{2 t} \mathbf{i}-2 \cos 3 t \mathbf{j} ; t_{0}=0$$
Step 1
This gives us the point of tangency. Substituting $t=0$ into $\mathbf{r}(t)$, we get $\mathbf{r}(0)=\mathbf{i}-2\mathbf{j}$, which simplifies to $\mathbf{r}(0)=1\mathbf{i}-2\mathbf{j}$. Show more…
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