Question
Find $(\partial u / \partial y)_{x}$ at the point $(u, v)=(\sqrt{2}, 1),$ if $x=u^{2}+v^{2}$ and $y=u v .$
Step 1
We need to find the partial derivative of $u$ with respect to $y$ at the point $(u, v)=(\sqrt{2}, 1)$, keeping $x$ as a constant. Show more…
Show all steps
Your feedback will help us improve your experience
Subham Jyoti Mishra and 83 other Calculus 3 educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
Find $(\partial u / \partial y)_{x}$ at the point $(u, v)=(\sqrt{2}, 1)$ if $x=u^{2}+v^{2}$ and $y=u v .$
Partial Derivatives
Partial Derivatives with Constrained Variables
Compute $\partial z / \partial u$ and $\partial z / \partial v$. $$ z=2 e^{x^{2} y} ; x=\sqrt{u v}, y=1 / u $$
The Chain Rule
$$ \begin{array}{l}{\text { Find } \quad \partial w / \partial v \quad \text { when } \quad u=0, v=0 \quad \text { if } \quad w=x^{2}+(y / x)} \\ {x=u-2 v+1, y=2 u+v-2}\end{array} $$
Transcript
Watch the video solution with this free unlock.
EMAIL
PASSWORD