Question
Find symmetric equations of the line of intersection of the planes $2 x+y-z=6$ and $x-y+3 z=4$
Step 1
Step 1: First, we add the two given plane equations: \[2x + x + y - y - z + 3z = 6 + 4\] This simplifies to: \[3x + 2z = 10\] From this, we can express $x$ in terms of $z$: \[x = \frac{10 - 2z}{3}\] Show more…
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