The derivative of the function is given by $\frac{dy}{dx} = \frac{dy/dt}{dx/dt}$. Here, $y = t^{3} - t$ and $x = 3t^{2}$. So, we have $\frac{dy}{dt} = 3t^{2} - 1$ and $\frac{dx}{dt} = 6t$. Therefore, $\frac{dy}{dx} = \frac{3t^{2} - 1}{6t}$.
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