Question
Find $t$ intervals on which the curve $x=3 t^{2}, y=t^{3}-t$ is concave up as well as concave down.
Step 1
We have $x = 3t^2$ and $y = t^3 - t$. The derivative of $x$ with respect to $t$ is $\frac{dx}{dt} = 6t$ and the derivative of $y$ with respect to $t$ is $\frac{dy}{dt} = 3t^2 - 1$. Show more…
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Key Concepts
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