00:01
In this problem of series we have given this is the sigma, this is n is equal to one lower limit and the upper limit is infinity and minus 5 minus 1 divided with 4 to the power n.
00:16
And now in this series we have to find third, fourth and fifth partial sum of this series.
00:22
So for finding the third partial sum, so this would be from n to 3 for finding 4th, this would be from n is equal to 1 to 4 and then 4.
00:30
For finding fifth this will be from 1 to 5 so this is here from n equals to 1 to 3 so this would be here 5 minus 1 4 to the power n for finding the 4th this would be from n is equal to 1 to 4 this is 5 multiplied with minus 1 divide with 4 to the power n and now for the 5th this would be from n is equal to 1 to 5th so this is 5 minus 1 to the 4 to the power n.
01:05
Now, solve it.
01:07
So this is 5, so this would be out of the box.
01:09
And now, from 1, the first term would be minus 1 divided with 4.
01:14
And then this would be here, say, 1 divide with 60 and then this would be from here.
01:21
That is minus 1 divide with 64.
01:25
And now solve it...