00:01
For this problem, we're asked to find the absolute maximum and absolute minimum values of e to the x divided by the quantity 1 plus x squared on the interval from 0 to 3.
00:11
So let's find the derivative of f to learn a little bit more about this function.
00:17
So we use the quotient rule of e to the x times 1 plus x squared, and then minus e to the x times 2x.
00:33
All of this is over 1 plus x squared quantity squared.
00:41
Okay, so i can factor out in either the x on top, and then i'm left with x squared minus 2x plus 1.
00:52
All of that is still over 1 plus x squared, quantity squared.
00:59
And the nice thing about the numerator is this last half factors as x minus 1 quantity squared and again i still have the same denominator okay so i can actually set f prime of x equal to zero and see if there's either an absolute or local maximum or minimum and if i do this i get that x equals 1 right because if i set this fraction equal to 0 when a fraction is equal to zero that that means that the numerator must be equal to zero.
01:47
And e to the x is never equal to zero...