Question
Find the absolute maximum and absolute minimum values of $f$ on the given interval.$f(x)=\frac{x}{x^{2}+1},[0,2]$
Step 1
We can do this by using the quotient rule, which states that the derivative of $\frac{u}{v}$ is $\frac{vu'-uv'}{v^2}$. Here, $u=x$ and $v=x^2+1$. So, $u'=1$ and $v'=2x$. Applying the quotient rule, we Show more…
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