00:01
For this question, we're asked to find the absolute maximums and minimums with f of x is equal to 2 thirds or x minus 5.
00:06
On the domain, negative 2 is less than you to x, which is less than equal to 3.
00:11
So to start off with, let's find the first derivative of f of x, the f prime of x, which would just get us 2 thirds.
00:18
And because we know that 0 is number equal to 2 thirds, we know that there is no critical numbers.
00:26
So we know that absolute maximum, awesome minimum, because we know that 2 thirds to x minus 5 is continuous and me.
00:32
We'll have to be at the size of a domain.
00:34
So we have an f of negative 2, which will get us negative 19 over 3.
00:39
And we have f of 3, which will get us negative 3.
00:46
And so then based on this, we know that this is going to be our absolute minimum.
00:56
And this over here is going to be our absolute maximum...