00:01
Here we have the function f of x equal to 3x squared minus 2x cubed on the closed interval from negative 5 to 1.
00:08
So we first take the derivative of our function, so that would be f prime of x.
00:15
Okay, so we take the derivative here, term by term, and see the derivative is well 6x minus 6x squared.
00:25
Okay, and then we go ahead and we take a derivative and we set it equal to 0.
00:30
Well, we have a common factor of 6x.
00:33
So if we factor out a 6x, we have 6x times, well, times 1 minus x, is then equal to 0.
00:42
Okay, well, this is true with either 6x is equal to 0 or 1 minus x is equal to 0.
00:47
That means that either x is equal to 0 or x is equal to 1.
00:53
So we have critical values of x being equal to zero, this is a zero, or x is equal to one.
01:03
So then we go ahead and we list out our critical values and our endpoints.
01:07
But notice that one of our endpoints, namely one, is also a critical value.
01:11
So our critical values and endpoints are negative 5, 0, and 1.
01:19
And then we evaluate the original function f at those three values...