00:01
So our function here is f of x is equal to 1 minus x cubed.
00:04
On the closed interval from negative 8 to 8.
00:07
So we first take our derivative.
00:10
So the derivative of our function would be f prime of x.
00:13
So that would just be equal to a negative 3x squared.
00:18
Okay? and then we take our derivative and we set it equal to zero and find the values of x that make the derivative equal to zero.
00:25
Well, if we take negative 3x squared and we set that equal to zero, well, okay, we get x and we can divide by negative 3 and take the square root, we just get that x is equal to zero.
00:37
So x here is equal to zero would be our critical value.
00:42
So then we list out the critical, all critical values we find and the endpoints.
00:47
So we have the endpoint of negative 8 and then a critical value of 0 and the other endpoint of 8.
00:53
And then we evaluate the original function at those values.
00:57
So we do f...