00:01
In this question, we are required to evaluate the accumulation function f for the function f alpha is equal to integration minus 1 to alpha, cosine pi theta by 2, d theta.
00:23
After that, we are required to find the value of f and we need to plot the graph for the f at alpha is equal to minus 1, 0 and 1 upon 2.
00:45
So let's see how to solve this question.
00:49
So first of all, let's integrate the above function to calculate the value of f alpha.
00:57
So f alpha will be equal to integration minus 1 to alpha, cosine pi theta by 2, d theta, and and the integration of cosine pi theta by 2 d theta will be equals to 2 upon pi, sine pi theta by 2 and the limits are minus 1 to alpha.
01:30
Now substitute the limits.
01:36
So we get f alpha is equal to 2 upon pi into sine pi alpha by 2 plus 1.
01:49
And now substitute alpha is equal to minus 1.
01:57
So we get minus 1 is equal to 2 upon pi into sine minus pi by 2 plus 1.
02:15
Since the value of sine minus pi by 2 is equals to minus 1, so the value of f minus 1 will be equals to 0 and the plot for f minus 1 is shown below so this is the plot for f minus 1 and f minus 1 is equals to 0 is the final answer for part a so now let's move to part b substitute alpha is equal to 0 in the integrated function of f so we get f0 is equal to 2 upon pi sine 0 plus 1...