We set $y=x^{2}$ equal to $y=x^{3}$ and solve for $x$. This gives us $x^{2}=x^{3}$, which simplifies to $x^{2}-x^{3}=0$. Factoring out $x^{2}$ gives $x^{2}(1-x)=0$. Setting each factor equal to zero gives $x=0$ and $x=1$. So, the points of intersection are $(0,0)$
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