The dot product of two vectors $\mathbf{u}$ and $\mathbf{v}$ is given by $\mathbf{u} \cdot \mathbf{v} = u_1v_1 + u_2v_2$. In this case, $\mathbf{u} = 2\mathbf{i}$ and $\mathbf{v} = -3\mathbf{j}$, so the dot product is $2 \cdot 0 + 0 \cdot -3 = 0$.
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