Question
Find the arc length of the graph of the function over the indicated interval.$x=\frac{1}{3}\left(y^{2}+2\right)^{3 / 2}, \quad 0 \leq y \leq 4$
Step 1
Using the chain rule, we get \[x' = \frac{1}{2}\left(y^{2}+2\right)^{1 / 2} \cdot 2y = y\sqrt{y^{2}+2}\] Show more…
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