Question
Find the area $A$ of the parallelogram with one corner at $P$ and sides $P Q$ and $P R$. $P=(-2,1,6) ; \quad Q=(2,1,-7) ; \quad R=(4,1,1)$
Step 1
We can find these vectors by subtracting the coordinates of point $P$ from the coordinates of points $Q$ and $R$ respectively. The vector $\vec{PQ}$ is given by $Q - P = (2 - (-2), 1 - 1, -7 - 6) = (4, 0, -13)$. The vector $\vec{PR}$ is given by $R - P = (4 - Show more…
Show all steps
Your feedback will help us improve your experience
Monica Miller and 78 other Calculus 3 educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
Find the area $A$ of the parallelogram with one corner at $P$ and sides $P Q$ and $P R$. $P=(1,-3,7) ; \quad Q=(2,1,1) ; \quad R=(6,-1,2)$
Vectors; Lines, Planes, and Quadric Surfaces in Space
The Cross Product
Find the area $A$ of the parallelogram with one corner at $P$ and sides $P Q$ and $P R$. $P=(-4,6,3) ; \quad Q=(1,1,-5) ; \quad R=(2,2,2)$
Find the area $A$ of the parallelogram with one corner at $P$ and sides $P Q$ and $P R$. $P=(1,1,-6) ; \quad Q=(5,-3,0) ; \quad R=(-2,4,1)$
Transcript
Watch the video solution with this free unlock.
EMAIL
PASSWORD