00:01
I don't find the area bounded by x and y x and the third, root x plus, 2 ,0, 2 ,0 .2, 1 in first quarter.
00:07
This is 4 by that, we have root x plus 4.
00:10
We use parametration here we have.
00:13
So, in parametric form, we can take x as 4theta to the power 4, y is 9, theta, the power 4 here we have.
00:26
This we have got now.
00:27
0 less than equal to theta less than 2 pi.
00:33
So we just work on this, we have got to 1.
00:35
Graph it is here we have theta goes to let's say 0 then y becomes 0 and x become 1 got this point then if theta goes to pi over 2 then x coming out to be 0 and y coming out to be 1 so it's going to be here the graph here the parameteration name is similarly on the second quadrant we get this on third quarter and we get this and 4th point in devils so this uh point here this is 1 comma 0 so in the first quadrant we'll find this area here we find this area we go like y dx we go here now y dx if we go here um dx is 0 to 1 we go here now that's coming out to be so y is sine here to the bar 4 right and then d x is the d x over d theta time d theta for parameterization which we have done in parametric form and then theta is coming out to be we have so axis 0 axis 0 we have uh theta is given as pi over 2.
01:47
When x is 1, so cost 0 is 1, theta is 0 being happened...