The derivative of $y=e^x$ is also $y=e^x$. So, the slope of the tangent line at $x=1$ is $e^1=e$. The point of tangency is $(1,e)$, so the equation of the tangent line is $y=mx+b$, where $m$ is the slope and $b$ is the y-intercept. Substituting the point and the
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