Question
Find the area of the intersection of the circles $r=\sin \theta$ and $r=$ $\sqrt{3} \cos \theta$
Step 1
We can do this by setting the two equations equal to each other and solving for $\theta$: \[\sin \theta = \sqrt{3} \cos \theta\] This simplifies to $\tan \theta = \sqrt{3}$, which gives us $\theta = \frac{\pi}{3}$ and $\theta = \frac{4\pi}{3}$. Show more…
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