The bases are AB and CD. We can use the distance formula to find these lengths. The distance formula is given by $\sqrt{(x_2-x_1)^2 + (y_2-y_1)^2}$.
For AB, we have $A(4,8)$ and $B(2,3)$. So, $AB = \sqrt{(2-4)^2 + (3-8)^2} = \sqrt{4 + 25} = \sqrt{29}$.
For CD,
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