Find the area of the quadrilateral whose vertices, taken in order, are $(-4,-2),(-3,-5)$, $(3,-2)$ and $(2,3)$

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Geometry

NCERT Class 10 - Math

Chapter 7

Coordinate Geometry

Section 3

Section Formula

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Video Transcript

we have our number four in which we need to find the area of the triangle area of the coordinator. Who is what is there taken in order? So let us write quarry little as uh this is a -4 Common- to B minus three comma minus five. C three Grammar -2 & D. Two commentary. Okay so basically this is the combination of two triangles, two triangles strangle A BD and triangle BCD. So we'll be just finding the idea of the jungles and then we'll add no we have a formula to find the area of the triangle. Area of the triangle is always equal to one x 2. X one Y Tu -Y. three. Bless X two. Why three -J. 1 plus X three and oh I want minus white. So we'll be using this formula. Okay? So let us find first the area of strangle a BD. Okay but this and we have Excellent means -4 and this is -5 -3. After that place -3 3 -2 -2 and place two into minus two minus minus five. So this will be a 32 or 1 # two and 2 32 minus 15 plus six 38 and minus 15 25 23 23 x two squadrons similarly Area of a triangle CBD CBD will be equal to half 3 -1 -3 Plus -3 and two three minus ah minus two Plus two and 2 minus two minus minus five. This is one x 2 83 11. No there were three and to not minus So they should be -24 minus 24 and uh -15 plus six. So uh this has to be equal to 30 minus 33 x two. What area should be positive so they can stay model this So it was three x 2. Quite the unit total area area of quadrilateral A B c D will be 23 x two. PL 33 x two 56 x two. That is 26. It's quiet unit. Thank you.

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