Question
Find the area of the region bounded by the curves $y=3 e^{-x / 3}, y=0, x=0,$ and $x=9 .$ Make a sketch.
Step 1
The area under a curve from a to b is given by the integral from a to b of the function. In this case, our function is $y=3e^{-x/3}$, and we are finding the area from $x=0$ to $x=9$. So, our integral is: $$\int_{0}^{9} 3e^{-x/3} dx$$ Show more…
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